What is 4(-3)^2+7(-2)^3 ?

The solution to 4(-3)^2+7(-2)^3 is -20

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4(-3)^2+7(-2)^3

4 (- 3)^{2} + 7 (- 2)^{3}

- 20

Solution steps

4 (- 3)^{2} + 7 (- 2)^{3}

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 4 \cdot 9 + 7 (- 2)^{3}

Calculate exponents

(- 2)^{3} : - 8

(- 2)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 2)^{3} = - 2^{3} = - 8

= - 8

= 4 \cdot 9 + 7 (- 8)

Multiply and divide (left to right)

4 \cdot 9 : 36

4 \cdot 9

4 \cdot 9 = 36

= 36

= 36 + 7 (- 8)

Multiply and divide (left to right)

7 (- 8) : - 56

7 (- 8)

Apply rule

a \cdot (- b) = - a \cdot b

7 (- 8) = - 7 \cdot 8 = - 56

= - 56

= 36 - 56

Add and subtract (left to right)

36 - 56 : - 20

36 - 56

36 - 56 = - 20

= - 20

= - 20

6^{2} - 2 (5 + 1 + 3)

2^{5} \cdot 5^{2}

1^{2} + 2

\frac{15}{94}

\frac{10}{11}