What is 2 1/3 \times (-5) 2/5 ?

The solution to 2 1/3 \times (-5) 2/5 is -14/3

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2 1/3 \times (-5) 2/5

2 \frac{1}{3} \cdot (- 5) \frac{2}{5}

- \frac{14}{3}

Solution steps

2 \frac{1}{3} \cdot (- 5) \frac{2}{5}

Convert mixed numbers to improper fractions:

2 \frac{1}{3} = \frac{7}{3}

2 \frac{1}{3}

Convert mixed numbers to improper fraction:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

2 \frac{1}{3} = \frac{2 \cdot 3 + 1}{3}

= \frac{7}{3}

= \frac{7}{3} \cdot (- 5) \frac{2}{5}

Follow the PEMDAS order of operations

Multiply and divide (left to right)

\frac{7}{3} (- 5) \frac{2}{5} : - \frac{14}{3}

\frac{7}{3} (- 5) \frac{2}{5}

\frac{7}{3} \cdot (- 5) = - \frac{35}{3}

\frac{7}{3} (- 5)

Apply rule

a \cdot (- b) = - a \cdot b

\frac{7}{3} (- 5) = - \frac{7}{3} \cdot 5

Convert element to fraction:

5 = \frac{5}{1}

= - \frac{7}{3} \cdot \frac{5}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{7}{3} \cdot \frac{5}{1} = \frac{7 \cdot 5}{3 \cdot 1}

= - \frac{7 \cdot 5}{3 \cdot 1}

Multiply the numbers:

7 \cdot 5 = 35

= - \frac{35}{3 \cdot 1}

Multiply the numbers:

3 \cdot 1 = 3

= - \frac{35}{3}

= - \frac{35}{3} \cdot \frac{2}{5}

- \frac{35}{3} \frac{2}{5} = - \frac{14}{3}

- \frac{35}{3} \cdot \frac{2}{5}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{35}{3} \cdot \frac{2}{5} = \frac{35 \cdot 2}{3 \cdot 5}

= - \frac{35 \cdot 2}{3 \cdot 5}

Cancel

\frac{35 \cdot 2}{3 \cdot 5} : \frac{14}{3}

\frac{35 \cdot 2}{3 \cdot 5}

Factor the number:

35 = 5 \cdot 7

= \frac{5 \cdot 7 \cdot 2}{3 \cdot 5}

Cancel the common factor:

5

= \frac{7 \cdot 2}{3}

Multiply the numbers:

7 \cdot 2 = 14

= \frac{14}{3}

= - \frac{14}{3}

= - \frac{14}{3}

= - \frac{14}{3}

4 - 2 (5 - 2 (4 - 2)) \div 24 - 2 (5 - 2 (4 - 2)) \div 2

15 - (- 18 - (- 12 + 15))

- 3 + 4 (+ 7 - 9 + 2)

3 \times 8 - 4 + 16 \div 4

1 2^{2} + 3 7^{2}