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인기 있는 삼각법 >

sin^2(x/2)+cos(x)>0

해법

sin^{2} (\frac{x}{2}) + cos (x) > 0

해법

π + 4 πn < x < 3 π + 4 πn

+2

간격 표기법

(π + 4 πn, 3 π + 4 πn)

소수

3.14159 \dots + 4 πn < x < 9.42477 \dots + 4 πn

솔루션 단계

sin^{2} (\frac{x}{2}) + cos (x) > 0

하게:

u = \frac{x}{2}

sin^{2} (u) + cos (2 u) > 0

sin^{2} (u) + cos (2 u) > 0 : - \frac{π}{2} + 2 πn < u < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < u < \frac{3 π}{2} + 2 πn

sin^{2} (u) + cos (2 u) > 0

다음 신원을 사용:

cos (2 x) = cos^{2} (x) - sin^{2} (x)

cos^{2} (u) - sin^{2} (u) + sin^{2} (u) > 0

단순화

cos^{2} (u) > 0

u^{n} > 0

위한,

n

균등하다 이면 그렇다면

u < 0

or

u > 0

cos (u) < 0 or cos (u) > 0

cos (u) < 0 : \frac{π}{2} + 2 πn < u < \frac{3 π}{2} + 2 πn

cos (u) < 0

위해서

cos (x) < a

, 이면

- 1 < a \leq 1

그렇다면

arccos (a) + 2 πn < x < 2 π - arccos (a) + 2 πn

arccos (0) + 2 πn < u < 2 π - arccos (0) + 2 πn

arccos (0)

간소화하다 :

\frac{π}{2}

arccos (0)

다음과 같은 사소한 아이덴티티 사용:

arccos (0) = \frac{π}{2}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{2}

2 π - arccos (0)

간소화하다 :

\frac{3 π}{2}

2 π - arccos (0)

다음과 같은 사소한 아이덴티티 사용:

arccos (0) = \frac{π}{2}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= 2 π - \frac{π}{2}

단순화

2 π - \frac{π}{2}

요소를 분수로 변환:

2 π = \frac{2 π 2}{2}

= \frac{2 π 2}{2} - \frac{π}{2}

분모가 같기 때문에, 분수를 합친다:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 π 2 - π}{2}

2 π 2 - π = 3 π

2 π 2 - π

숫자를 곱하시오:

2 \cdot 2 = 4

= 4 π - π

유사 요소 추가:

4 π - π = 3 π

= 3 π

= \frac{3 π}{2}

= \frac{3 π}{2}

\frac{π}{2} + 2 πn < u < \frac{3 π}{2} + 2 πn

cos (u) > 0 : - \frac{π}{2} + 2 πn < u < \frac{π}{2} + 2 πn

cos (u) > 0

위해서

cos (x) > a

, 이면

- 1 \leq a < 1

그렇다면

- arccos (a) + 2 πn < x < arccos (a) + 2 πn

- arccos (0) + 2 πn < u < arccos (0) + 2 πn

- arccos (0)

간소화하다 :

- \frac{π}{2}

- arccos (0)

다음과 같은 사소한 아이덴티티 사용:

arccos (0) = \frac{π}{2}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= - \frac{π}{2}

arccos (0)

간소화하다 :

\frac{π}{2}

arccos (0)

다음과 같은 사소한 아이덴티티 사용:

arccos (0) = \frac{π}{2}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{2}

- \frac{π}{2} + 2 πn < u < \frac{π}{2} + 2 πn

간격 결합

\frac{π}{2} + 2 πn < u < \frac{3 π}{2} + 2 πn or - \frac{π}{2} + 2 πn < u < \frac{π}{2} + 2 πn

중복 구간 병합

- \frac{π}{2} + 2 πn < u < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < u < \frac{3 π}{2} + 2 πn

- \frac{π}{2} + 2 πn < u < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < u < \frac{3 π}{2} + 2 πn

뒤로 대체

\frac{x}{2} = u

- \frac{π}{2} + 2 πn < (\frac{x}{2}) < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < (\frac{x}{2}) < \frac{3 π}{2} + 2 πn

- \frac{π}{2} + 2 πn < (\frac{x}{2}) < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < (\frac{x}{2}) < \frac{3 π}{2} + 2 πn : π + 4 πn < x < 3 π + 4 πn

- \frac{π}{2} + 2 πn < (\frac{x}{2}) < \frac{π}{2} + 2 πn or \frac{π}{2} + 2 πn < (\frac{x}{2}) < \frac{3 π}{2} + 2 πn

- \frac{π}{2} + 2 πn < \frac{x}{2} < \frac{π}{2} + 2 πn :

모두에게 거짓입니다

x \in R

- \frac{π}{2} + 2 πn < \frac{x}{2} < \frac{π}{2} + 2 πn

만약에

a < u < b

그렇다면

a < u and u < b

- \frac{π}{2} + 2 πn < \frac{x}{2} and \frac{x}{2} < \frac{π}{2} + 2 πn

- \frac{π}{2} + 2 πn < \frac{x}{2} : x > - π + 4 πn

- \frac{π}{2} + 2 πn < \frac{x}{2}

측면 전환

\frac{x}{2} > - \frac{π}{2} + 2 πn

양쪽을 곱한 값

2

\frac{x}{2} > - \frac{π}{2} + 2 πn

양쪽을 곱한 값

2

\frac{2 x}{2} > - 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

단순화

\frac{2 x}{2} > - 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

\frac{2 x}{2}

간소화하다 :

x

\frac{2 x}{2}

숫자를 나눕니다:

\frac{2}{2} = 1

= x

- 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

간소화하다 :

- π + 4 πn

- 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

2 \cdot \frac{π}{2} = π

2 \cdot \frac{π}{2}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{2}

공통 요인 취소:

2

= π

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

숫자를 곱하시오:

2 \cdot 2 = 4

= 4 πn

= - π + 4 πn

x > - π + 4 πn

x > - π + 4 πn

x > - π + 4 πn

\frac{x}{2} < \frac{π}{2} + 2 πn : x < π + 4 πn

\frac{x}{2} < \frac{π}{2} + 2 πn

양쪽을 곱한 값

2

\frac{x}{2} < \frac{π}{2} + 2 πn

양쪽을 곱한 값

2

\frac{2 x}{2} < 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

단순화

\frac{2 x}{2} < 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

\frac{2 x}{2}

간소화하다 :

x

\frac{2 x}{2}

숫자를 나눕니다:

\frac{2}{2} = 1

= x

2 \cdot \frac{π}{2} + 2 \cdot 2 πn

간소화하다 :

π + 4 πn

2 \cdot \frac{π}{2} + 2 \cdot 2 πn

2 \cdot \frac{π}{2} = π

2 \cdot \frac{π}{2}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{2}

공통 요인 취소:

2

= π

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

숫자를 곱하시오:

2 \cdot 2 = 4

= 4 πn

= π + 4 πn

x < π + 4 πn

x < π + 4 πn

x < π + 4 πn

간격 결합

x > - π + 4 πn and x < π + 4 πn

중복 구간 병합

모두에게 거짓입니다 x \in R

\frac{π}{2} + 2 πn < \frac{x}{2} < \frac{3 π}{2} + 2 πn : π + 4 πn < x < 3 π + 4 πn

\frac{π}{2} + 2 πn < \frac{x}{2} < \frac{3 π}{2} + 2 πn

만약에

a < u < b

그렇다면

a < u and u < b

\frac{π}{2} + 2 πn < \frac{x}{2} and \frac{x}{2} < \frac{3 π}{2} + 2 πn

\frac{π}{2} + 2 πn < \frac{x}{2} : x > π + 4 πn

\frac{π}{2} + 2 πn < \frac{x}{2}

측면 전환

\frac{x}{2} > \frac{π}{2} + 2 πn

양쪽을 곱한 값

2

\frac{x}{2} > \frac{π}{2} + 2 πn

양쪽을 곱한 값

2

\frac{2 x}{2} > 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

단순화

\frac{2 x}{2} > 2 \cdot \frac{π}{2} + 2 \cdot 2 πn

\frac{2 x}{2}

간소화하다 :

x

\frac{2 x}{2}

숫자를 나눕니다:

\frac{2}{2} = 1

= x

2 \cdot \frac{π}{2} + 2 \cdot 2 πn

간소화하다 :

π + 4 πn

2 \cdot \frac{π}{2} + 2 \cdot 2 πn

2 \cdot \frac{π}{2} = π

2 \cdot \frac{π}{2}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{2}

공통 요인 취소:

2

= π

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

숫자를 곱하시오:

2 \cdot 2 = 4

= 4 πn

= π + 4 πn

x > π + 4 πn

x > π + 4 πn

x > π + 4 πn

\frac{x}{2} < \frac{3 π}{2} + 2 πn : x < 3 π + 4 πn

\frac{x}{2} < \frac{3 π}{2} + 2 πn

양쪽을 곱한 값

2

\frac{x}{2} < \frac{3 π}{2} + 2 πn

양쪽을 곱한 값

2

\frac{2 x}{2} < 2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

단순화

\frac{2 x}{2} < 2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

\frac{2 x}{2}

간소화하다 :

x

\frac{2 x}{2}

숫자를 나눕니다:

\frac{2}{2} = 1

= x

2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

간소화하다 :

3 π + 4 πn

2 \cdot \frac{3 π}{2} + 2 \cdot 2 πn

2 \cdot \frac{3 π}{2} = 3 π

2 \cdot \frac{3 π}{2}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 π 2}{2}

공통 요인 취소:

2

= 3 π

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

숫자를 곱하시오:

2 \cdot 2 = 4

= 4 πn

= 3 π + 4 πn

x < 3 π + 4 πn

x < 3 π + 4 πn

x < 3 π + 4 πn

간격 결합

x > π + 4 πn and x < 3 π + 4 πn

중복 구간 병합

π + 4 πn < x < 3 π + 4 πn

간격 결합

모두에게 거짓입니다 x \in R or π + 4 πn < x < 3 π + 4 πn

중복 구간 병합

π + 4 πn < x < 3 π + 4 πn

π + 4 πn < x < 3 π + 4 πn

인기 있는 예

cos(x)>-(sqrt(3))/2

cos (x) > - \frac{3}{2}

pi/2-arctan(x^6)<0.0001

\frac{π}{2} - arctan (x^{6}) < 0.0001

2sin(x)cos(x)>cos(x)

2 sin (x) cos (x) > cos (x)

tan(θ)<= sqrt(3)

tan (θ) \leq 3

1-4(cos(x)sin(x/2))>= 0

1 - 4 (cos (x) sin (\frac{x}{2})) \geq 0