cos(x)-2+2=1

Lösung

cos (x) - 2 + 2 = 1

x = 2 πn

Grad

x = 0^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (x) - 2 + 2 = 1

- 2 + 2 = 0

cos (x) = 1

Allgemeine Lösung für

cos (x) = 1

cos (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

Löse

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

- 3 + cos (2 x) 2 = 0

cos (θ) cos (3 θ) - 1 = 0

2 tan (θ) sin (θ) - tan (θ) = 0

sin (4 x + \frac{π}{4}) = 1

cos^{2} (x) - cos (x) = 0, (0, 2 π)