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Beliebt Trigonometrie >

sin^2(θ)+cos(2θ)=0

Lösung

sin^{2} (θ) + cos (2 θ) = 0

Lösung

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

+1

Grad

θ = 9 0^{\circ} + 36 0^{\circ} n, θ = 27 0^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

sin^{2} (θ) + cos (2 θ) = 0

Umschreiben mit Hilfe von Trigonometrie-Identitäten

cos (2 θ) + sin^{2} (θ)

Verwende die Doppelwinkelidentität:

cos^{2} (x) - sin^{2} (x) = cos (2 x)

- sin^{2} (x) = cos (2 x) - cos^{2} (x)

= cos (2 θ) - (cos (2 θ) - cos^{2} (θ))

Vereinfache

cos (2 θ) - (cos (2 θ) - cos^{2} (θ)) : cos^{2} (θ)

cos (2 θ) - (cos (2 θ) - cos^{2} (θ))

- (cos (2 θ) - cos^{2} (θ)) : - cos (2 θ) + cos^{2} (θ)

- (cos (2 θ) - cos^{2} (θ))

Setze Klammern

= - (cos (2 θ)) - (- cos^{2} (θ))

Wende Minus-Plus Regeln an

- (- a) = a, - (a) = - a

= - cos (2 θ) + cos^{2} (θ)

= cos (2 θ) - cos (2 θ) + cos^{2} (θ)

Addiere gleiche Elemente:

cos (2 θ) - cos (2 θ) = 0

= cos^{2} (θ)

= cos^{2} (θ)

cos^{2} (θ) = 0

Wende Regel an

x^{n} = 0 \Rightarrow x = 0

cos (θ) = 0

Allgemeine Lösung für

cos (θ) = 0

cos (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

θ = \frac{π}{2} + 2 πn, θ = \frac{3 π}{2} + 2 πn

Graph

Beliebte Beispiele

csc(θ)=(sqrt(28))/2 ,sin(θ)

csc (θ) = \frac{28}{2}, sin (θ)

(1+csc(γ))/(cot(γ)+cos(γ))=csc(γ)

\frac{1 + csc ( γ )}{cot ( γ ) + cos ( γ )} = csc (γ)

sin (θ) = \frac{2}{6}

3 sin (2 x) = - 2

solvefor x,arctan(y)=2arctan(x)

so l v e f or x, arctan (y) = 2 arctan (x)