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product rule derivative of (2-3x(x^2+5x-1))

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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product rule ddx ((2−3x)(x²+5x−1))

Solution

−9x²−26x+13

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ddx ((2−3x)(x²+5x−1))

Apply the Product Rule: (f·g)′=f ′·g+f·g′

f=2−3x, g=x²+5x−1

=ddx (2−3x)(x²+5x−1)+ddx (x²+5x−1)(2−3x)

ddx (2−3x)=−3

ddx (x²+5x−1)=2x+5

=(−3)(x²+5x−1)+(2x+5)(2−3x)

Simplify (−3)(x²+5x−1)+(2x+5)(2−3x): −9x²−26x+13

=−9x²−26x+13

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

product rule derivative of (2-3x(x^2+5x-1))

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