What are the solutions to the equation roots x^2+16 ?

The solutions to the equation roots x^2+16 are x=4i,x=-4i

Find the zeros of roots x^2+16

The zeros of roots x^2+16 are x=4i,x=-4i

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roots

x^{2} + 16

x = 4 i, x = - 4 i

Solution steps

x^{2} + 16

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 16 = 0

Move

16

to the right side

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

x^{2} + 6 x + c

x^{2} - 4 x + 1

3 x^{2} + 11 x = 4

x^{2} + x - 1

- x^{2} - 4 x - 2

What are the solutions to the equation roots x^2+16 ?
The solutions to the equation roots x^2+16 are x=4i,x=-4i
Find the zeros of roots x^2+16
The zeros of roots x^2+16 are x=4i,x=-4i