What are the solutions to the equation 5(x+3)^2-3=42 ?

The solutions to the equation 5(x+3)^2-3=42 are x=0,x=-6

Find the zeros of 5(x+3)^2-3=42

The zeros of 5(x+3)^2-3=42 are x=0,x=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 (x + 3)^{2} - 3 = 42

x = 0, x = - 6

Solution steps

5 (x + 3)^{2} - 3 = 42

Move

3

to the right side

5 (x + 3)^{2} = 45

Divide both sides by

5

(x + 3)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 9 : x = 0

Solve

x + 3 = - 9 : x = - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

x^{2} + 4 x + 4 = 3 x + 10

6 x^{2} + 2 x - 28 = 0

4 x^{2} - 5 x - 6 = 0

16 x^{2} + 2400 x = 0

x^{2} - 2 x + 2 = 4

What are the solutions to the equation 5(x+3)^2-3=42 ?
The solutions to the equation 5(x+3)^2-3=42 are x=0,x=-6
Find the zeros of 5(x+3)^2-3=42
The zeros of 5(x+3)^2-3=42 are x=0,x=-6