What is the answer to solvefor y,x^2y-x^2+4y=0 ?

The answer to solvefor y,x^2y-x^2+4y=0 is y=(x^2)/(x^2+4);\quad x\ne 2i,x\ne-2i

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solvefor y,x^2y-x^2+4y=0

solve for

y, x^{2} y - x^{2} + 4 y = 0

y = \frac{x ^{2}}{x ^{2} + 4}; x \neq = 2 i, x \neq = - 2 i

Solution steps

x^{2} y - x^{2} + 4 y = 0

Move

x^{2}

to the right side

x^{2} y + 4 y = x^{2}

Factor

x^{2} y + 4 y : y (x^{2} + 4)

y (x^{2} + 4) = x^{2}

Divide both sides by

x^{2} + 4; x \neq = 2 i, x \neq = - 2 i

y = \frac{x ^{2}}{x ^{2} + 4}; x \neq = 2 i, x \neq = - 2 i

25 b^{2} + 24 b + 9 = - 6 b

5 x^{2} - 31 x - 28 = 0

5 k^{2} - 28 k + 19 = 4

x^{2} + 2 x - 13 = 130

- 4 x^{2} - 24 x + 64 = 0

What is the answer to solvefor y,x^2y-x^2+4y=0 ?
The answer to solvefor y,x^2y-x^2+4y=0 is y=(x^2)/(x^2+4);\quad x\ne 2i,x\ne-2i