What are the solutions to the equation roots x^2-4x-5 ?

The solutions to the equation roots x^2-4x-5 are x=5,x=-1

Find the zeros of roots x^2-4x-5

The zeros of roots x^2-4x-5 are x=5,x=-1

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roots

x^{2} - 4 x - 5

x = 5, x = - 1

Solution steps

x^{2} - 4 x - 5

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

30.252 x^{2} - 1290 x + 2946.667 = 0

y, 2 x^{2} + x y + y^{2} = 4

12 b^{2} + 21 b + 10 = 3 b^{2}

15 c^{2} - c - 20 = 3 c^{2}

2 x^{2} + 82 = - 24 x

What are the solutions to the equation roots x^2-4x-5 ?
The solutions to the equation roots x^2-4x-5 are x=5,x=-1
Find the zeros of roots x^2-4x-5
The zeros of roots x^2-4x-5 are x=5,x=-1