What are the solutions to the equation 15q^2+31q+15=5 ?

The solutions to the equation 15q^2+31q+15=5 are q=-2/5 ,q=-5/3

Find the zeros of 15q^2+31q+15=5

The zeros of 15q^2+31q+15=5 are q=-2/5 ,q=-5/3

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15 q^{2} + 31 q + 15 = 5

q = - \frac{2}{5}, q = - \frac{5}{3}

Decimal

q = - 0.4, q = - 1.66666 \dots

Solution steps

15 q^{2} + 31 q + 15 = 5

Move

5

to the left side

15 q^{2} + 31 q + 10 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 \cdot 15 \cdot 10}{2 \cdot 15}

3 1^{2} - 4 \cdot 15 \cdot 10 = 19

q_{1, 2} = \frac{- 31 \pm 19}{2 \cdot 15}

Separate the solutions

q_{1} = \frac{- 31 + 19}{2 \cdot 15}, q_{2} = \frac{- 31 - 19}{2 \cdot 15}

q = \frac{- 31 + 19}{2 \cdot 15} : - \frac{2}{5}

q = \frac{- 31 - 19}{2 \cdot 15} : - \frac{5}{3}

The solutions to the quadratic equation are:

q = - \frac{2}{5}, q = - \frac{5}{3}

12 x^{2} - 32 = 0

- 5 x^{2} + x = 0

x, z = 9 - x^{2} - y^{2}

x^{2} - 3 x + 2 = 0

3 q^{2} + 5 q - 8 = 0

What are the solutions to the equation 15q^2+31q+15=5 ?
The solutions to the equation 15q^2+31q+15=5 are q=-2/5 ,q=-5/3
Find the zeros of 15q^2+31q+15=5
The zeros of 15q^2+31q+15=5 are q=-2/5 ,q=-5/3