What are the solutions to the equation roots x^2-12x+c ?

The solutions to the equation roots x^2-12x+c are x=6+sqrt(-c+36),x=6-sqrt(-c+36)

Find the zeros of roots x^2-12x+c

The zeros of roots x^2-12x+c are x=6+sqrt(-c+36),x=6-sqrt(-c+36)

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roots

x^{2} - 12 x + c

x = 6 + - c + 36, x = 6 - - c + 36

Solution steps

x^{2} - 12 x + c

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 12 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot c}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot c : 2 36 - c

x_{1, 2} = \frac{- ( - 12 ) \pm 2 36 - c}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 36 - c}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 36 - c}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 36 - c}{2 \cdot 1} : 6 + - c + 36

x = \frac{- ( - 12 ) - 2 36 - c}{2 \cdot 1} : 6 - - c + 36

The solutions to the quadratic equation are:

x = 6 + - c + 36, x = 6 - - c + 36

220900 x^{2} - 4760 x + 16 = 0

z^{2} - 3 z + 4 = 0

y, 3 x^{2} + 2 x y + 5 y^{2} = 24

\frac{4}{3} x^{2} - 6 = - 70

5 (2 x + 9)^{2} - 21 = 4

What are the solutions to the equation roots x^2-12x+c ?
The solutions to the equation roots x^2-12x+c are x=6+sqrt(-c+36),x=6-sqrt(-c+36)
Find the zeros of roots x^2-12x+c
The zeros of roots x^2-12x+c are x=6+sqrt(-c+36),x=6-sqrt(-c+36)