What are the solutions to the equation 3c^2+14c-8=4c ?

The solutions to the equation 3c^2+14c-8=4c are c= 2/3 ,c=-4

Find the zeros of 3c^2+14c-8=4c

The zeros of 3c^2+14c-8=4c are c= 2/3 ,c=-4

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3 c^{2} + 14 c - 8 = 4 c

c = \frac{2}{3}, c = - 4

Decimal

c = 0.66666 \dots, c = - 4

Solution steps

3 c^{2} + 14 c - 8 = 4 c

Move

4 c

to the left side

3 c^{2} + 10 c - 8 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 8) = 14

c_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 3}

Separate the solutions

c_{1} = \frac{- 10 + 14}{2 \cdot 3}, c_{2} = \frac{- 10 - 14}{2 \cdot 3}

c = \frac{- 10 + 14}{2 \cdot 3} : \frac{2}{3}

c = \frac{- 10 - 14}{2 \cdot 3} : - 4

The solutions to the quadratic equation are:

c = \frac{2}{3}, c = - 4

2 x^{2} = 73728

r^{2} + 20 r + 1000 = 0

x^{2} - 2 x + 3

x^{2} + 4 x + 3 = 0

f, f (x + 2) = (x + 2)^{2} + 1

What are the solutions to the equation 3c^2+14c-8=4c ?
The solutions to the equation 3c^2+14c-8=4c are c= 2/3 ,c=-4
Find the zeros of 3c^2+14c-8=4c
The zeros of 3c^2+14c-8=4c are c= 2/3 ,c=-4