What are the solutions to the equation roots-2(x+9)(x-1) ?

The solutions to the equation roots-2(x+9)(x-1) are x=-9,x=1

Find the zeros of roots-2(x+9)(x-1)

The zeros of roots-2(x+9)(x-1) are x=-9,x=1

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roots

- 2 (x + 9) (x - 1)

x = - 9, x = 1

Solution steps

- 2 (x + 9) (x - 1)

The roots are the intercepts with the x-axis

(y = 0)

- 2 (x + 9) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 9 = 0 or x - 1 = 0

Solve

x + 9 = 0 : x = - 9

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = - 9, x = 1

2 a^{2} - a - 11 = - 3

2 x^{2} + 82 = - 24 x

y, x^{2} + x = y^{2} + y

3 x^{2} + 7 x + 4 = 0

5 y^{2} + 13 y + 12 = 6

What are the solutions to the equation roots-2(x+9)(x-1) ?
The solutions to the equation roots-2(x+9)(x-1) are x=-9,x=1
Find the zeros of roots-2(x+9)(x-1)
The zeros of roots-2(x+9)(x-1) are x=-9,x=1