What are the solutions to the equation 3x^2-4x-12=10 ?

The solutions to the equation 3x^2-4x-12=10 are x=(2+sqrt(70))/3 ,x=(2-sqrt(70))/3

Find the zeros of 3x^2-4x-12=10

The zeros of 3x^2-4x-12=10 are x=(2+sqrt(70))/3 ,x=(2-sqrt(70))/3

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3 x^{2} - 4 x - 12 = 10

x = \frac{2 + 70}{3}, x = \frac{2 - 70}{3}

Decimal

x = 3.45553 \dots, x = - 2.12220 \dots

Solution steps

3 x^{2} - 4 x - 12 = 10

Move

10

to the left side

3 x^{2} - 4 x - 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 22 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 22) = 270

x_{1, 2} = \frac{- ( - 4 ) \pm 2 70}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 70}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 70}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 70}{2 \cdot 3} : \frac{2 + 70}{3}

x = \frac{- ( - 4 ) - 2 70}{2 \cdot 3} : \frac{2 - 70}{3}

The solutions to the quadratic equation are:

x = \frac{2 + 70}{3}, x = \frac{2 - 70}{3}

- 5 z^{2} + 9 z + 13 = - 6 z^{2}

9 n^{2} + 4 n - 4 = 0

(3 x - 3) (6 x - 12) = 0

18 x^{2} - 98 = 0

(x^{2} - 5 x + 25) = 0

What are the solutions to the equation 3x^2-4x-12=10 ?
The solutions to the equation 3x^2-4x-12=10 are x=(2+sqrt(70))/3 ,x=(2-sqrt(70))/3
Find the zeros of 3x^2-4x-12=10
The zeros of 3x^2-4x-12=10 are x=(2+sqrt(70))/3 ,x=(2-sqrt(70))/3