What are the solutions to the equation 4d^2+2d-2=3d ?

The solutions to the equation 4d^2+2d-2=3d are d=(1+sqrt(33))/8 ,d=(1-sqrt(33))/8

Find the zeros of 4d^2+2d-2=3d

The zeros of 4d^2+2d-2=3d are d=(1+sqrt(33))/8 ,d=(1-sqrt(33))/8

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4 d^{2} + 2 d - 2 = 3 d

d = \frac{1 + 33}{8}, d = \frac{1 - 33}{8}

Decimal

d = 0.84307 \dots, d = - 0.59307 \dots

Solution steps

4 d^{2} + 2 d - 2 = 3 d

Move

3 d

to the left side

4 d^{2} - d - 2 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 (- 2) = 33

d_{1, 2} = \frac{- ( - 1 ) \pm 33}{2 \cdot 4}

Separate the solutions

d_{1} = \frac{- ( - 1 ) + 33}{2 \cdot 4}, d_{2} = \frac{- ( - 1 ) - 33}{2 \cdot 4}

d = \frac{- ( - 1 ) + 33}{2 \cdot 4} : \frac{1 + 33}{8}

d = \frac{- ( - 1 ) - 33}{2 \cdot 4} : \frac{1 - 33}{8}

The solutions to the quadratic equation are:

d = \frac{1 + 33}{8}, d = \frac{1 - 33}{8}

81 x^{2} + 198 x + 121 = 0

v, F = \frac{m v ^{2}}{r ^{2}}

3 + x = x^{2} + 3 x

x^{2} + 2 x + 17

0 = x^{2} + 20 x - 60

What are the solutions to the equation 4d^2+2d-2=3d ?
The solutions to the equation 4d^2+2d-2=3d are d=(1+sqrt(33))/8 ,d=(1-sqrt(33))/8
Find the zeros of 4d^2+2d-2=3d
The zeros of 4d^2+2d-2=3d are d=(1+sqrt(33))/8 ,d=(1-sqrt(33))/8