What are the solutions to the equation 2n^2-9n+5=2n ?

The solutions to the equation 2n^2-9n+5=2n are n=5,n= 1/2

Find the zeros of 2n^2-9n+5=2n

The zeros of 2n^2-9n+5=2n are n=5,n= 1/2

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2 n^{2} - 9 n + 5 = 2 n

n = 5, n = \frac{1}{2}

Decimal

n = 5, n = 0.5

Solution steps

2 n^{2} - 9 n + 5 = 2 n

Move

2 n

to the left side

2 n^{2} - 11 n + 5 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 \cdot 5 = 9

n_{1, 2} = \frac{- ( - 11 ) \pm 9}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- ( - 11 ) + 9}{2 \cdot 2}, n_{2} = \frac{- ( - 11 ) - 9}{2 \cdot 2}

n = \frac{- ( - 11 ) + 9}{2 \cdot 2} : 5

n = \frac{- ( - 11 ) - 9}{2 \cdot 2} : \frac{1}{2}

The solutions to the quadratic equation are:

n = 5, n = \frac{1}{2}

x^{2} + 4 x - 21 = 0

2 x^{2} + 12 x + 8

6 w^{2} - 26 w + 5 = w^{2}

5 x^{2} = - 28 x + 12

2 x^{2} + 4 x = 30

What are the solutions to the equation 2n^2-9n+5=2n ?
The solutions to the equation 2n^2-9n+5=2n are n=5,n= 1/2
Find the zeros of 2n^2-9n+5=2n
The zeros of 2n^2-9n+5=2n are n=5,n= 1/2