What are the solutions to the equation 12x^2-36x-48=0 ?

The solutions to the equation 12x^2-36x-48=0 are x=4,x=-1

Find the zeros of 12x^2-36x-48=0

The zeros of 12x^2-36x-48=0 are x=4,x=-1

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12 x^{2} - 36 x - 48 = 0

x = 4, x = - 1

Solution steps

12 x^{2} - 36 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 12 ( - 48 )}{2 \cdot 12}

(- 36)^{2} - 4 \cdot 12 (- 48) = 60

x_{1, 2} = \frac{- ( - 36 ) \pm 60}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 60}{2 \cdot 12}, x_{2} = \frac{- ( - 36 ) - 60}{2 \cdot 12}

x = \frac{- ( - 36 ) + 60}{2 \cdot 12} : 4

x = \frac{- ( - 36 ) - 60}{2 \cdot 12} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

(9 x - 15)^{2} - 2 (9 x - 15) + 1 = 0

x^{2} + x - 12 = 0

3 x^{2} + 5 x - 100 = 0

y, y^{2} + y - x^{2} - x = 0

(3 x + 8)^{2} + 21 = 47

What are the solutions to the equation 12x^2-36x-48=0 ?
The solutions to the equation 12x^2-36x-48=0 are x=4,x=-1
Find the zeros of 12x^2-36x-48=0
The zeros of 12x^2-36x-48=0 are x=4,x=-1