What are the solutions to the equation 7x^2-47=128 ?

The solutions to the equation 7x^2-47=128 are x=5,x=-5

Find the zeros of 7x^2-47=128

The zeros of 7x^2-47=128 are x=5,x=-5

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7 x^{2} - 47 = 128

x = 5, x = - 5

Solution steps

7 x^{2} - 47 = 128

Move

47

to the right side

7 x^{2} = 175

Divide both sides by

7

x^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 25, x = - 25

25 = 5

- 25 = - 5

x = 5, x = - 5

\frac{1}{4} x^{2} - 4 = 0

4 m^{2} - 5 m - 3 = 2 m

x^{2} - 9 x + 3 = 3

x^{2} + 27 = - 11 x + 3

y, x^{2} y - x y^{2} + x^{2} + y^{2} = 0

What are the solutions to the equation 7x^2-47=128 ?
The solutions to the equation 7x^2-47=128 are x=5,x=-5
Find the zeros of 7x^2-47=128
The zeros of 7x^2-47=128 are x=5,x=-5