What are the solutions to the equation roots x^2-4x-3 ?

The solutions to the equation roots x^2-4x-3 are x=2+sqrt(7),x=2-sqrt(7)

Find the zeros of roots x^2-4x-3

The zeros of roots x^2-4x-3 are x=2+sqrt(7),x=2-sqrt(7)

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roots

x^{2} - 4 x - 3

x = 2 + 7, x = 2 - 7

Solution steps

x^{2} - 4 x - 3

The roots are the intercepts with the x-axis

(y = 0)

x^{2} - 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 3) = 27

x_{1, 2} = \frac{- ( - 4 ) \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 7}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 7}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 7}{2 \cdot 1} : 2 + 7

x = \frac{- ( - 4 ) - 2 7}{2 \cdot 1} : 2 - 7

The solutions to the quadratic equation are:

x = 2 + 7, x = 2 - 7

22 q^{2} + 16 q - 5 = 6 q^{2}

15 = 5 x^{2}

18 x^{2} = 8

x^{2} + 3 x - 10 = 0

x^{2} + 24 x + 44 = - 19

What are the solutions to the equation roots x^2-4x-3 ?
The solutions to the equation roots x^2-4x-3 are x=2+sqrt(7),x=2-sqrt(7)
Find the zeros of roots x^2-4x-3
The zeros of roots x^2-4x-3 are x=2+sqrt(7),x=2-sqrt(7)