What are the solutions to the equation 22q^2+16q-5=6q^2 ?

The solutions to the equation 22q^2+16q-5=6q^2 are q= 1/4 ,q=-5/4

Find the zeros of 22q^2+16q-5=6q^2

The zeros of 22q^2+16q-5=6q^2 are q= 1/4 ,q=-5/4

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22 q^{2} + 16 q - 5 = 6 q^{2}

q = \frac{1}{4}, q = - \frac{5}{4}

Decimal

q = 0.25, q = - 1.25

Solution steps

22 q^{2} + 16 q - 5 = 6 q^{2}

Move

6 q^{2}

to the left side

16 q^{2} + 16 q - 5 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 16 ( - 5 )}{2 \cdot 16}

1 6^{2} - 4 \cdot 16 (- 5) = 24

q_{1, 2} = \frac{- 16 \pm 24}{2 \cdot 16}

Separate the solutions

q_{1} = \frac{- 16 + 24}{2 \cdot 16}, q_{2} = \frac{- 16 - 24}{2 \cdot 16}

q = \frac{- 16 + 24}{2 \cdot 16} : \frac{1}{4}

q = \frac{- 16 - 24}{2 \cdot 16} : - \frac{5}{4}

The solutions to the quadratic equation are:

q = \frac{1}{4}, q = - \frac{5}{4}

15 = 5 x^{2}

18 x^{2} = 8

x^{2} + 3 x - 10 = 0

x^{2} + 24 x + 44 = - 19

2 π r^{2} + 120 π r - 1507.9 = 0

What are the solutions to the equation 22q^2+16q-5=6q^2 ?
The solutions to the equation 22q^2+16q-5=6q^2 are q= 1/4 ,q=-5/4
Find the zeros of 22q^2+16q-5=6q^2
The zeros of 22q^2+16q-5=6q^2 are q= 1/4 ,q=-5/4