What are the solutions to the equation 4a^2+a-6=0 ?

The solutions to the equation 4a^2+a-6=0 are a=(-1+sqrt(97))/8 ,a=(-1-sqrt(97))/8

Find the zeros of 4a^2+a-6=0

The zeros of 4a^2+a-6=0 are a=(-1+sqrt(97))/8 ,a=(-1-sqrt(97))/8

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4 a^{2} + a - 6 = 0

a = \frac{- 1 + 97}{8}, a = \frac{- 1 - 97}{8}

Decimal

a = 1.10610 \dots, a = - 1.35610 \dots

Solution steps

4 a^{2} + a - 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 6 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 6) = 97

a_{1, 2} = \frac{- 1 \pm 97}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- 1 + 97}{2 \cdot 4}, a_{2} = \frac{- 1 - 97}{2 \cdot 4}

a = \frac{- 1 + 97}{2 \cdot 4} : \frac{- 1 + 97}{8}

a = \frac{- 1 - 97}{2 \cdot 4} : \frac{- 1 - 97}{8}

The solutions to the quadratic equation are:

a = \frac{- 1 + 97}{8}, a = \frac{- 1 - 97}{8}

- 12 x^{2} + 48 x = 0

14 x^{2} - 5 = 33 x

- 2 x^{2} - 20 x - 6

4 d^{2} + 17 d + 10 = - d^{2}

15 - x^{2} = - 14

What are the solutions to the equation 4a^2+a-6=0 ?
The solutions to the equation 4a^2+a-6=0 are a=(-1+sqrt(97))/8 ,a=(-1-sqrt(97))/8
Find the zeros of 4a^2+a-6=0
The zeros of 4a^2+a-6=0 are a=(-1+sqrt(97))/8 ,a=(-1-sqrt(97))/8