What are the solutions to the equation (x+5)(x+8)=180 ?

The solutions to the equation (x+5)(x+8)=180 are x=7,x=-20

Find the zeros of (x+5)(x+8)=180

The zeros of (x+5)(x+8)=180 are x=7,x=-20

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(x + 5) (x + 8) = 180

x = 7, x = - 20

Solution steps

(x + 5) (x + 8) = 180

Expand

(x + 5) (x + 8) : x^{2} + 13 x + 40

x^{2} + 13 x + 40 = 180

Move

180

to the left side

x^{2} + 13 x - 140 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot ( - 140 )}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot (- 140) = 27

x_{1, 2} = \frac{- 13 \pm 27}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 27}{2 \cdot 1}, x_{2} = \frac{- 13 - 27}{2 \cdot 1}

x = \frac{- 13 + 27}{2 \cdot 1} : 7

x = \frac{- 13 - 27}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

x = 7, x = - 20

4 x^{2} - 2.90827 x + 0.528679 = 0

2 x^{2} + 14 = 70

2 x^{2} + x - 6 = 0

3 x^{2} + 5 = - 142

(2 x - 3) (x + 6) = 8

What are the solutions to the equation (x+5)(x+8)=180 ?
The solutions to the equation (x+5)(x+8)=180 are x=7,x=-20
Find the zeros of (x+5)(x+8)=180
The zeros of (x+5)(x+8)=180 are x=7,x=-20