What is the answer to solvefor y,x^2y-4x=5 ?

The answer to solvefor y,x^2y-4x=5 is y=(5+4x)/(x^2);\quad x\ne 0

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solvefor y,x^2y-4x=5

solve for

y, x^{2} y - 4 x = 5

y = \frac{5 + 4 x}{x ^{2}}; x \neq = 0

Solution steps

x^{2} y - 4 x = 5

Move

4 x

to the right side

x^{2} y = 5 + 4 x

Divide both sides by

x^{2}; x \neq = 0

y = \frac{5 + 4 x}{x ^{2}}; x \neq = 0

2 x^{2} + 6 x = - 4

y, x^{2} y^{2} = 3 x

x^{2} - 40 = - 6 x

\frac{3}{2} y^{2} - 6 y = \frac{3}{4} y - 9

36 = x^{2} + x^{2}

What is the answer to solvefor y,x^2y-4x=5 ?
The answer to solvefor y,x^2y-4x=5 is y=(5+4x)/(x^2);\quad x\ne 0