What are the solutions to the equation (x-2)^2=3x-2 ?

The solutions to the equation (x-2)^2=3x-2 are x=6,x=1

Find the zeros of (x-2)^2=3x-2

The zeros of (x-2)^2=3x-2 are x=6,x=1

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(x - 2)^{2} = 3 x - 2

x = 6, x = 1

Solution steps

(x - 2)^{2} = 3 x - 2

Expand

(x - 2)^{2} : x^{2} - 4 x + 4

x^{2} - 4 x + 4 = 3 x - 2

Move

2

to the left side

x^{2} - 4 x + 6 = 3 x

Move

3 x

to the left side

x^{2} - 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 6 = 5

x_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 1}

x = \frac{- ( - 7 ) + 5}{2 \cdot 1} : 6

x = \frac{- ( - 7 ) - 5}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 6, x = 1

h^{2} + 5 h = 295

16 z^{2} - 40 z + 31 = 6

- 0.25 x^{2} + 6 x + 20 = 0

y, x^{2} y^{2} + 5 x y = 14

6 x^{2} + 24 x - 126 = 0

What are the solutions to the equation (x-2)^2=3x-2 ?
The solutions to the equation (x-2)^2=3x-2 are x=6,x=1
Find the zeros of (x-2)^2=3x-2
The zeros of (x-2)^2=3x-2 are x=6,x=1