What are the solutions to the equation 2x^2+160=36x ?

The solutions to the equation 2x^2+160=36x are x=10,x=8

Find the zeros of 2x^2+160=36x

The zeros of 2x^2+160=36x are x=10,x=8

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2 x^{2} + 160 = 36 x

x = 10, x = 8

Solution steps

2 x^{2} + 160 = 36 x

Move

36 x

to the left side

2 x^{2} + 160 - 36 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - 36 x + 160 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 2 \cdot 160}{2 \cdot 2}

(- 36)^{2} - 4 \cdot 2 \cdot 160 = 4

x_{1, 2} = \frac{- ( - 36 ) \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 4}{2 \cdot 2}, x_{2} = \frac{- ( - 36 ) - 4}{2 \cdot 2}

x = \frac{- ( - 36 ) + 4}{2 \cdot 2} : 10

x = \frac{- ( - 36 ) - 4}{2 \cdot 2} : 8

The solutions to the quadratic equation are:

x = 10, x = 8

y, y^{2} + 2 y + 1 = 0

t, \frac{A t - ( B t ^{2} )}{2} = 0

(2 x - 1) (x + 2) = 8 x - 4

3 x^{2} - 26 = 1

x^{2} - 3 x - 19 = 0

What are the solutions to the equation 2x^2+160=36x ?
The solutions to the equation 2x^2+160=36x are x=10,x=8
Find the zeros of 2x^2+160=36x
The zeros of 2x^2+160=36x are x=10,x=8