What are the solutions to the equation -2x^2+6x=-6 ?

The solutions to the equation -2x^2+6x=-6 are x=-(-3+sqrt(21))/2 ,x=(3+sqrt(21))/2

Find the zeros of -2x^2+6x=-6

The zeros of -2x^2+6x=-6 are x=-(-3+sqrt(21))/2 ,x=(3+sqrt(21))/2

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- 2 x^{2} + 6 x = - 6

x = - \frac{- 3 + 21}{2}, x = \frac{3 + 21}{2}

Decimal

x = - 0.79128 \dots, x = 3.79128 \dots

Solution steps

- 2 x^{2} + 6 x = - 6

Move

6

to the left side

- 2 x^{2} + 6 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

6^{2} - 4 (- 2) \cdot 6 = 221

x_{1, 2} = \frac{- 6 \pm 2 21}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 21}{2 ( - 2 )}, x_{2} = \frac{- 6 - 2 21}{2 ( - 2 )}

x = \frac{- 6 + 2 21}{2 ( - 2 )} : - \frac{- 3 + 21}{2}

x = \frac{- 6 - 2 21}{2 ( - 2 )} : \frac{3 + 21}{2}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 21}{2}, x = \frac{3 + 21}{2}

5 x^{2} + 84 = - 36

5 k^{2} - 9 k + 18 = 4 k^{2}

0 = 4 x^{2} - 16 x

10 x - \frac{5}{2} x^{2} = 10

x^{2} + 1.2 x + 1 = 0

What are the solutions to the equation -2x^2+6x=-6 ?
The solutions to the equation -2x^2+6x=-6 are x=-(-3+sqrt(21))/2 ,x=(3+sqrt(21))/2
Find the zeros of -2x^2+6x=-6
The zeros of -2x^2+6x=-6 are x=-(-3+sqrt(21))/2 ,x=(3+sqrt(21))/2