What are the solutions to the equation 3a^2-4a=4 ?

The solutions to the equation 3a^2-4a=4 are a=2,a=-2/3

Find the zeros of 3a^2-4a=4

The zeros of 3a^2-4a=4 are a=2,a=-2/3

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3 a^{2} - 4 a = 4

a = 2, a = - \frac{2}{3}

Decimal

a = 2, a = - 0.66666 \dots

Solution steps

3 a^{2} - 4 a = 4

Move

4

to the left side

3 a^{2} - 4 a - 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 (- 4) = 8

a_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 3}, a_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 3}

a = \frac{- ( - 4 ) + 8}{2 \cdot 3} : 2

a = \frac{- ( - 4 ) - 8}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

a = 2, a = - \frac{2}{3}

6 x^{2} - 3 x = 2, y - 5 - 2 x^{2} + x = y - 4

x^{2} - 4 x + 11

- 3 x^{2} + 2 x + 7 = 0

2 y^{2} + 2 = 9 y

5 z^{2} - 20 z + 25 = z^{2}

What are the solutions to the equation 3a^2-4a=4 ?
The solutions to the equation 3a^2-4a=4 are a=2,a=-2/3
Find the zeros of 3a^2-4a=4
The zeros of 3a^2-4a=4 are a=2,a=-2/3