What is 6x^2-3x=2,y-5-2x^2+x=y-4 ?

The solution to 6x^2-3x=2,y-5-2x^2+x=y-4 is No Solution

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6x^2-3x=2,y-5-2x^2+x=y-4

6 x^{2} - 3 x = 2, y - 5 - 2 x^{2} + x = y - 4

No Solution

Solution steps

[6 x^{2} - 3 x = 2 y - 5 - 2 x^{2} + x = y - 4]

Isolate

x^{2}

for

y - 5 - 2 x^{2} + x = y - 4 : x^{2} = - \frac{- x + 1}{2}

Plug the solutions

x^{2} = - \frac{- x + 1}{2}

into

6 x^{2} - 3 x = 2

For

6 x^{2} - 3 x = 2

, subsitute

x^{2}

with

- \frac{- x + 1}{2} :

No Solution

No Solution

x^{2} - 4 x + 11

- 3 x^{2} + 2 x + 7 = 0

2 y^{2} + 2 = 9 y

5 z^{2} - 20 z + 25 = z^{2}

3 m^{2} - 4 m - 4 = m

What is 6x^2-3x=2,y-5-2x^2+x=y-4 ?
The solution to 6x^2-3x=2,y-5-2x^2+x=y-4 is No Solution