What are the solutions to the equation 94-q=q^2 ?

The solutions to the equation 94-q=q^2 are q=(-1+sqrt(377))/2 ,q=(-1-sqrt(377))/2

Find the zeros of 94-q=q^2

The zeros of 94-q=q^2 are q=(-1+sqrt(377))/2 ,q=(-1-sqrt(377))/2

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94 - q = q^{2}

q = \frac{- 1 + 377}{2}, q = \frac{- 1 - 377}{2}

Decimal

q = 9.20824 \dots, q = - 10.20824 \dots

Solution steps

94 - q = q^{2}

Switch sides

q^{2} = 94 - q

Move

q

to the left side

q^{2} + q = 94

Move

94

to the left side

q^{2} + q - 94 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 94 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 94) = 377

q_{1, 2} = \frac{- 1 \pm 377}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 1 + 377}{2 \cdot 1}, q_{2} = \frac{- 1 - 377}{2 \cdot 1}

q = \frac{- 1 + 377}{2 \cdot 1} : \frac{- 1 + 377}{2}

q = \frac{- 1 - 377}{2 \cdot 1} : \frac{- 1 - 377}{2}

The solutions to the quadratic equation are:

q = \frac{- 1 + 377}{2}, q = \frac{- 1 - 377}{2}

3 x^{2} + 5 x - 2

- 12 = - 3 (x - 3)^{2}

x^{2} - x + \frac{6}{25} = 0

\frac{1}{7} p^{2} = \frac{5}{7} p^{2} - 20

2 x^{2} + 12 x - 3

What are the solutions to the equation 94-q=q^2 ?
The solutions to the equation 94-q=q^2 are q=(-1+sqrt(377))/2 ,q=(-1-sqrt(377))/2
Find the zeros of 94-q=q^2
The zeros of 94-q=q^2 are q=(-1+sqrt(377))/2 ,q=(-1-sqrt(377))/2