What are the solutions to the equation 18x-6=9x^2 ?

The solutions to the equation 18x-6=9x^2 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3

Find the zeros of 18x-6=9x^2

The zeros of 18x-6=9x^2 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3

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18 x - 6 = 9 x^{2}

x = \frac{3 + 3}{3}, x = \frac{3 - 3}{3}

Decimal

x = 1.57735 \dots, x = 0.42264 \dots

Solution steps

18 x - 6 = 9 x^{2}

Switch sides

9 x^{2} = 18 x - 6

Move

6

to the left side

9 x^{2} + 6 = 18 x

Move

18 x

to the left side

9 x^{2} + 6 - 18 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 18 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 6}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 \cdot 6 = 63

x_{1, 2} = \frac{- ( - 18 ) \pm 6 3}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 3}{2 \cdot 9}, x_{2} = \frac{- ( - 18 ) - 6 3}{2 \cdot 9}

x = \frac{- ( - 18 ) + 6 3}{2 \cdot 9} : \frac{3 + 3}{3}

x = \frac{- ( - 18 ) - 6 3}{2 \cdot 9} : \frac{3 - 3}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 3}{3}, x = \frac{3 - 3}{3}

y, x^{2} y^{2} + x y = 12

x^{2} - 5 x - 12 = - 5 x + 4

3 x^{2} + 2 x + a x^{2} + 5 a + 1 = 0

80 - 5 x^{2} = 0

z^{2} + 8 z + 15 = 0

What are the solutions to the equation 18x-6=9x^2 ?
The solutions to the equation 18x-6=9x^2 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3
Find the zeros of 18x-6=9x^2
The zeros of 18x-6=9x^2 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3