What are the solutions to the equation 6x^2-18x-24=81 ?

The solutions to the equation 6x^2-18x-24=81 are x=(3+sqrt(79))/2 ,x=(3-sqrt(79))/2

Find the zeros of 6x^2-18x-24=81

The zeros of 6x^2-18x-24=81 are x=(3+sqrt(79))/2 ,x=(3-sqrt(79))/2

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6 x^{2} - 18 x - 24 = 81

x = \frac{3 + 79}{2}, x = \frac{3 - 79}{2}

Decimal

x = 5.94409 \dots, x = - 2.94409 \dots

Solution steps

6 x^{2} - 18 x - 24 = 81

Move

81

to the left side

6 x^{2} - 18 x - 105 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 6 ( - 105 )}{2 \cdot 6}

(- 18)^{2} - 4 \cdot 6 (- 105) = 679

x_{1, 2} = \frac{- ( - 18 ) \pm 6 79}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 79}{2 \cdot 6}, x_{2} = \frac{- ( - 18 ) - 6 79}{2 \cdot 6}

x = \frac{- ( - 18 ) + 6 79}{2 \cdot 6} : \frac{3 + 79}{2}

x = \frac{- ( - 18 ) - 6 79}{2 \cdot 6} : \frac{3 - 79}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 79}{2}, x = \frac{3 - 79}{2}

x^{2} - 6 x + 18

x^{2} + 4 x = 6

x^{2} + 4 x = 5

3 x^{2} + 12 x = 7 x + 2

4 x^{2} - 9 = 0

What are the solutions to the equation 6x^2-18x-24=81 ?
The solutions to the equation 6x^2-18x-24=81 are x=(3+sqrt(79))/2 ,x=(3-sqrt(79))/2
Find the zeros of 6x^2-18x-24=81
The zeros of 6x^2-18x-24=81 are x=(3+sqrt(79))/2 ,x=(3-sqrt(79))/2