What are the solutions to the equation 3x^2+7x-24=13x ?

The solutions to the equation 3x^2+7x-24=13x are x=4,x=-2

Find the zeros of 3x^2+7x-24=13x

The zeros of 3x^2+7x-24=13x are x=4,x=-2

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3 x^{2} + 7 x - 24 = 13 x

x = 4, x = - 2

Solution steps

3 x^{2} + 7 x - 24 = 13 x

Move

13 x

to the left side

3 x^{2} - 6 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 24 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 24) = 18

x_{1, 2} = \frac{- ( - 6 ) \pm 18}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 18}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 18}{2 \cdot 3}

x = \frac{- ( - 6 ) + 18}{2 \cdot 3} : 4

x = \frac{- ( - 6 ) - 18}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = 4, x = - 2

3 x^{2} - 8 x + 4 = 0

x - 8 = 7 (x - 2) x

- 8 - 5 n^{2} = - 88

- 1 = t - t^{2}

1.5 x^{2} + 12 x + 24 = 0

What are the solutions to the equation 3x^2+7x-24=13x ?
The solutions to the equation 3x^2+7x-24=13x are x=4,x=-2
Find the zeros of 3x^2+7x-24=13x
The zeros of 3x^2+7x-24=13x are x=4,x=-2