What are the solutions to the equation 4(3x+8)^2+17=21 ?

The solutions to the equation 4(3x+8)^2+17=21 are x=-7/3 ,x=-3

Find the zeros of 4(3x+8)^2+17=21

The zeros of 4(3x+8)^2+17=21 are x=-7/3 ,x=-3

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4 (3 x + 8)^{2} + 17 = 21

x = - \frac{7}{3}, x = - 3

Decimal

x = - 2.33333 \dots, x = - 3

Solution steps

4 (3 x + 8)^{2} + 17 = 21

Move

17

to the right side

4 (3 x + 8)^{2} = 4

Divide both sides by

4

(3 x + 8)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 8 = 1 : x = - \frac{7}{3}

Solve

3 x + 8 = - 1 : x = - 3

The solutions to the quadratic equation are:

x = - \frac{7}{3}, x = - 3

y, 2 (x^{2} + y^{2}) = 25 (x^{2} - y^{2})

12 x^{2} - 5 x - 2 = 0

s^{2} + 6 s + 13

2 v^{2} + 4 v = - 10

2 q^{2} + 2 q - 1 = 0

What are the solutions to the equation 4(3x+8)^2+17=21 ?
The solutions to the equation 4(3x+8)^2+17=21 are x=-7/3 ,x=-3
Find the zeros of 4(3x+8)^2+17=21
The zeros of 4(3x+8)^2+17=21 are x=-7/3 ,x=-3