What are the solutions to the equation x^2+x-5=-x^2-5 ?

The solutions to the equation x^2+x-5=-x^2-5 are x=0,x=-1/2

Find the zeros of x^2+x-5=-x^2-5

The zeros of x^2+x-5=-x^2-5 are x=0,x=-1/2

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x^{2} + x - 5 = - x^{2} - 5

x = 0, x = - \frac{1}{2}

Decimal

x = 0, x = - 0.5

Solution steps

x^{2} + x - 5 = - x^{2} - 5

Move

5

to the left side

x^{2} + x = - x^{2}

Move

x^{2}

to the left side

2 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

1^{2} - 4 \cdot 2 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 \cdot 2}, x_{2} = \frac{- 1 - 1}{2 \cdot 2}

x = \frac{- 1 + 1}{2 \cdot 2} : 0

x = \frac{- 1 - 1}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{2}

1 - 6 x (1 - x) = 0

2 k^{2} + 11 k + 12 = 0

8 x^{2} - 10 = 3 x^{2} + 3

\frac{3}{4} (x + 3)^{2} = - 96

y, x^{2} + 4 x y + y^{2} = 0

What are the solutions to the equation x^2+x-5=-x^2-5 ?
The solutions to the equation x^2+x-5=-x^2-5 are x=0,x=-1/2
Find the zeros of x^2+x-5=-x^2-5
The zeros of x^2+x-5=-x^2-5 are x=0,x=-1/2