What are the solutions to the equation (55-x)(x)=750 ?

The solutions to the equation (55-x)(x)=750 are x=25,x=30

Find the zeros of (55-x)(x)=750

The zeros of (55-x)(x)=750 are x=25,x=30

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(55 - x) (x) = 750

x = 25, x = 30

Solution steps

(55 - x) (x) = 750

Expand

(55 - x) (x) : 55 x - x^{2}

55 x - x^{2} = 750

Move

750

to the left side

55 x - x^{2} - 750 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 55 x - 750 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 55 \pm 5 5 ^{2} - 4 ( - 1 ) ( - 750 )}{2 ( - 1 )}

5 5^{2} - 4 (- 1) (- 750) = 5

x_{1, 2} = \frac{- 55 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 55 + 5}{2 ( - 1 )}, x_{2} = \frac{- 55 - 5}{2 ( - 1 )}

x = \frac{- 55 + 5}{2 ( - 1 )} : 25

x = \frac{- 55 - 5}{2 ( - 1 )} : 30

The solutions to the quadratic equation are:

x = 25, x = 30

5 x^{2} = 6 x + 8

s^{2} + 0.5 s + 4 = 0

x^{2} - x + 1 = 0

n^{2} - 30 = - n

4 b^{2} - 5 b - 6 = - 2

What are the solutions to the equation (55-x)(x)=750 ?
The solutions to the equation (55-x)(x)=750 are x=25,x=30
Find the zeros of (55-x)(x)=750
The zeros of (55-x)(x)=750 are x=25,x=30