What are the solutions to the equation 4(x-5)^2=12 ?

The solutions to the equation 4(x-5)^2=12 are x=sqrt(3)+5,x=-sqrt(3)+5

Find the zeros of 4(x-5)^2=12

The zeros of 4(x-5)^2=12 are x=sqrt(3)+5,x=-sqrt(3)+5

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4 (x - 5)^{2} = 12

x = 3 + 5, x = - 3 + 5

Decimal

x = 6.73205 \dots, x = 3.26794 \dots

Solution steps

4 (x - 5)^{2} = 12

Divide both sides by

4

(x - 5)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 3 : x = 3 + 5

Solve

x - 5 = - 3 : x = - 3 + 5

The solutions to the quadratic equation are:

x = 3 + 5, x = - 3 + 5

8 p^{2} + 8 p - 4 = 3 p^{2}

2 x^{2} = 5 + 3 x

2 x^{2} = x^{2} + 81

n^{2} + 1 = - 10

- 5 x^{2} + 35 x - 50 = 0

What are the solutions to the equation 4(x-5)^2=12 ?
The solutions to the equation 4(x-5)^2=12 are x=sqrt(3)+5,x=-sqrt(3)+5
Find the zeros of 4(x-5)^2=12
The zeros of 4(x-5)^2=12 are x=sqrt(3)+5,x=-sqrt(3)+5