What are the solutions to the equation 14x+x^2=24 ?

The solutions to the equation 14x+x^2=24 are x=-7+sqrt(73),x=-7-sqrt(73)

Find the zeros of 14x+x^2=24

The zeros of 14x+x^2=24 are x=-7+sqrt(73),x=-7-sqrt(73)

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14 x + x^{2} = 24

x = - 7 + 73, x = - 7 - 73

Decimal

x = 1.54400 \dots, x = - 15.54400 \dots

Solution steps

14 x + x^{2} = 24

Move

24

to the left side

14 x + x^{2} - 24 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 14 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 24) = 273

x_{1, 2} = \frac{- 14 \pm 2 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 73}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 73}{2 \cdot 1}

x = \frac{- 14 + 2 73}{2 \cdot 1} : - 7 + 73

x = \frac{- 14 - 2 73}{2 \cdot 1} : - 7 - 73

The solutions to the quadratic equation are:

x = - 7 + 73, x = - 7 - 73

x^{2} - 3 (x - 3)^{2} = 2

x^{2} - 8

4 x^{2} + 1

x^{2} + 8 x = 9

5 x^{2} + 15 x = 40

What are the solutions to the equation 14x+x^2=24 ?
The solutions to the equation 14x+x^2=24 are x=-7+sqrt(73),x=-7-sqrt(73)
Find the zeros of 14x+x^2=24
The zeros of 14x+x^2=24 are x=-7+sqrt(73),x=-7-sqrt(73)