What are the solutions to the equation 0=3x^2-16x+24 ?

The solutions to the equation 0=3x^2-16x+24 are x= 8/3+i(2sqrt(2))/3 ,x= 8/3-i(2sqrt(2))/3

Find the zeros of 0=3x^2-16x+24

The zeros of 0=3x^2-16x+24 are x= 8/3+i(2sqrt(2))/3 ,x= 8/3-i(2sqrt(2))/3

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0 = 3 x^{2} - 16 x + 24

x = \frac{8}{3} + i \frac{2 2}{3}, x = \frac{8}{3} - i \frac{2 2}{3}

Solution steps

0 = 3 x^{2} - 16 x + 24

Switch sides

3 x^{2} - 16 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

Simplify

(- 16)^{2} - 4 \cdot 3 \cdot 24 : 42 i

x_{1, 2} = \frac{- ( - 16 ) \pm 4 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 2 i}{2 \cdot 3}, x_{2} = \frac{- ( - 16 ) - 4 2 i}{2 \cdot 3}

x = \frac{- ( - 16 ) + 4 2 i}{2 \cdot 3} : \frac{8}{3} + i \frac{2 2}{3}

x = \frac{- ( - 16 ) - 4 2 i}{2 \cdot 3} : \frac{8}{3} - i \frac{2 2}{3}

The solutions to the quadratic equation are:

x = \frac{8}{3} + i \frac{2 2}{3}, x = \frac{8}{3} - i \frac{2 2}{3}

4.9 x^{2} - 6 x - 20 = 0

x^{2} + 2 x - 35 = 0

y, χ y^{2} z^{3} = 2

0 = - 3 x^{2} + 4

10 n^{2} + 15 n - 25 = 6 n^{2}

What are the solutions to the equation 0=3x^2-16x+24 ?
The solutions to the equation 0=3x^2-16x+24 are x= 8/3+i(2sqrt(2))/3 ,x= 8/3-i(2sqrt(2))/3
Find the zeros of 0=3x^2-16x+24
The zeros of 0=3x^2-16x+24 are x= 8/3+i(2sqrt(2))/3 ,x= 8/3-i(2sqrt(2))/3