What are the solutions to the equation 16(x^2-5)+14=15 ?

The solutions to the equation 16(x^2-5)+14=15 are x= 9/4 ,x=-9/4

Find the zeros of 16(x^2-5)+14=15

The zeros of 16(x^2-5)+14=15 are x= 9/4 ,x=-9/4

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16 (x^{2} - 5) + 14 = 15

x = \frac{9}{4}, x = - \frac{9}{4}

Decimal

x = 2.25, x = - 2.25

Solution steps

16 (x^{2} - 5) + 14 = 15

Move

14

to the right side

16 (x^{2} - 5) = 1

Divide both sides by

16

x^{2} - 5 = \frac{1}{16}

Move

5

to the right side

x^{2} = \frac{81}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{81}{16}, x = - \frac{81}{16}

\frac{81}{16} = \frac{9}{4}

- \frac{81}{16} = - \frac{9}{4}

x = \frac{9}{4}, x = - \frac{9}{4}

5 (3 x - 3)^{2} - 44 = - 29

3 = 6 x^{2} + 6 x - 9

4 x^{2} - 3 x = - 3

3 x^{2} - 4 x - 4 = 3

9 r^{2} + 6 r + 4 = 0

What are the solutions to the equation 16(x^2-5)+14=15 ?
The solutions to the equation 16(x^2-5)+14=15 are x= 9/4 ,x=-9/4
Find the zeros of 16(x^2-5)+14=15
The zeros of 16(x^2-5)+14=15 are x= 9/4 ,x=-9/4