What are the solutions to the equation 6x^2+108x=-582 ?

The solutions to the equation 6x^2+108x=-582 are x=-9+4i,x=-9-4i

Find the zeros of 6x^2+108x=-582

The zeros of 6x^2+108x=-582 are x=-9+4i,x=-9-4i

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6 x^{2} + 108 x = - 582

x = - 9 + 4 i, x = - 9 - 4 i

Solution steps

6 x^{2} + 108 x = - 582

Move

582

to the left side

6 x^{2} + 108 x + 582 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 108 \pm 10 8 ^{2} - 4 \cdot 6 \cdot 582}{2 \cdot 6}

Simplify

10 8^{2} - 4 \cdot 6 \cdot 582 : 48 i

x_{1, 2} = \frac{- 108 \pm 48 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 108 + 48 i}{2 \cdot 6}, x_{2} = \frac{- 108 - 48 i}{2 \cdot 6}

x = \frac{- 108 + 48 i}{2 \cdot 6} : - 9 + 4 i

x = \frac{- 108 - 48 i}{2 \cdot 6} : - 9 - 4 i

The solutions to the quadratic equation are:

x = - 9 + 4 i, x = - 9 - 4 i

(x - 10) (x + 7) = 0

4 x^{2} = 18

x^{2} + 5 x + 25

4 (10 - 5 x)^{2} = 49

x^{2} - 2 x - 4

What are the solutions to the equation 6x^2+108x=-582 ?
The solutions to the equation 6x^2+108x=-582 are x=-9+4i,x=-9-4i
Find the zeros of 6x^2+108x=-582
The zeros of 6x^2+108x=-582 are x=-9+4i,x=-9-4i