What are the solutions to the equation 2x^2-11x+13=0 ?

The solutions to the equation 2x^2-11x+13=0 are x=(11+sqrt(17))/4 ,x=(11-sqrt(17))/4

Find the zeros of 2x^2-11x+13=0

The zeros of 2x^2-11x+13=0 are x=(11+sqrt(17))/4 ,x=(11-sqrt(17))/4

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2 x^{2} - 11 x + 13 = 0

x = \frac{11 + 17}{4}, x = \frac{11 - 17}{4}

Decimal

x = 3.78077 \dots, x = 1.71922 \dots

Solution steps

2 x^{2} - 11 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 2 \cdot 13}{2 \cdot 2}

(- 11)^{2} - 4 \cdot 2 \cdot 13 = 17

x_{1, 2} = \frac{- ( - 11 ) \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 17}{2 \cdot 2}, x_{2} = \frac{- ( - 11 ) - 17}{2 \cdot 2}

x = \frac{- ( - 11 ) + 17}{2 \cdot 2} : \frac{11 + 17}{4}

x = \frac{- ( - 11 ) - 17}{2 \cdot 2} : \frac{11 - 17}{4}

The solutions to the quadratic equation are:

x = \frac{11 + 17}{4}, x = \frac{11 - 17}{4}

470 = 1.33 x - 0.04 x^{2}

a^{2} + 10 a + 2 = 0

x^{2} - 2 (1) - 4 x = 0

- 4 x^{2} - 2 x + 6 = 0

0 = - 0.08 x^{2} + 40 x - 1800

What are the solutions to the equation 2x^2-11x+13=0 ?
The solutions to the equation 2x^2-11x+13=0 are x=(11+sqrt(17))/4 ,x=(11-sqrt(17))/4
Find the zeros of 2x^2-11x+13=0
The zeros of 2x^2-11x+13=0 are x=(11+sqrt(17))/4 ,x=(11-sqrt(17))/4