What are the solutions to the equation completesquare-4x^2+24x-41 ?

The solutions to the equation completesquare-4x^2+24x-41 are -4(x-3)^2-5

Find the zeros of completesquare-4x^2+24x-41

The zeros of completesquare-4x^2+24x-41 are -4(x-3)^2-5

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complete the square

- 4 x^{2} + 24 x - 41

- 4 (x - 3)^{2} - 5

Solution steps

- 4 x^{2} + 24 x - 41

Write

- 4 x^{2} + 24 x - 41

in the form:

x^{2} + 2 a x + a^{2}

Factor out

- 4

- 4 (x^{2} - 6 x + \frac{41}{4})

2 a = - 6 : a = - 3

Add and subtract

(- 3)^{2}

- 4 (x^{2} - 6 x + \frac{41}{4} + (- 3)^{2} - (- 3)^{2})

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} - 6 x + (- 3)^{2} = (x - 3)^{2}

- 4 ((x - 3)^{2} + \frac{41}{4} - (- 3)^{2})

Simplify

- 4 (x - 3)^{2} - 5

- 6 x^{2} = 72

c^{2} + c - 19 = 4 c

- x^{2} + 6 x = 10

y, x^{2} - x (y - 2) - 3 y = 0

x^{2} - \frac{11}{10} x + \frac{1}{10} = 0

What are the solutions to the equation completesquare-4x^2+24x-41 ?
The solutions to the equation completesquare-4x^2+24x-41 are -4(x-3)^2-5
Find the zeros of completesquare-4x^2+24x-41
The zeros of completesquare-4x^2+24x-41 are -4(x-3)^2-5