What are the solutions to the equation 4u^2+20u=-25 ?

The solutions to the equation 4u^2+20u=-25 are u=-5/2

Find the zeros of 4u^2+20u=-25

The zeros of 4u^2+20u=-25 are u=-5/2

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4 u^{2} + 20 u = - 25

u = - \frac{5}{2}

Decimal

u = - 2.5

Solution steps

4 u^{2} + 20 u = - 25

Move

25

to the left side

4 u^{2} + 20 u + 25 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

u_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

u = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

u = - \frac{5}{2}

The solution to the quadratic equation is:

u = - \frac{5}{2}

2 x^{2} - 9 x + 13 = 0

5 x^{2} + 7 = - 60

3 x^{2} - 2 x - 1

(x + 5)^{2} = 2 (x + 9)

x^{2} - 3 x - 10 = 0

What are the solutions to the equation 4u^2+20u=-25 ?
The solutions to the equation 4u^2+20u=-25 are u=-5/2
Find the zeros of 4u^2+20u=-25
The zeros of 4u^2+20u=-25 are u=-5/2