What are the solutions to the equation -2(x-1)(x+3)=0 ?

The solutions to the equation -2(x-1)(x+3)=0 are x=1,x=-3

Find the zeros of -2(x-1)(x+3)=0

The zeros of -2(x-1)(x+3)=0 are x=1,x=-3

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- 2 (x - 1) (x + 3) = 0

x = 1, x = - 3

Solution steps

- 2 (x - 1) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = 1, x = - 3

13 x^{2} = 16

u (u + 6) = 3

48 = 3 (x - 1)^{2}

x^{2} - 18 = - 7 x

x^{2} - 36 = 12 x

What are the solutions to the equation -2(x-1)(x+3)=0 ?
The solutions to the equation -2(x-1)(x+3)=0 are x=1,x=-3
Find the zeros of -2(x-1)(x+3)=0
The zeros of -2(x-1)(x+3)=0 are x=1,x=-3