What are the solutions to the equation (x+7)^2+4=68 ?

The solutions to the equation (x+7)^2+4=68 are x=1,x=-15

Find the zeros of (x+7)^2+4=68

The zeros of (x+7)^2+4=68 are x=1,x=-15

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(x + 7)^{2} + 4 = 68

x = 1, x = - 15

Solution steps

(x + 7)^{2} + 4 = 68

Move

4

to the right side

(x + 7)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 64 : x = 1

Solve

x + 7 = - 64 : x = - 15

The solutions to the quadratic equation are:

x = 1, x = - 15

0.1125 x^{2} = 35

x^{2} + 3 \times (- 28) = 0

y, e^{y} = x^{2}

x + 12 x^{2} = 6

(x) (x) = 2 x

What are the solutions to the equation (x+7)^2+4=68 ?
The solutions to the equation (x+7)^2+4=68 are x=1,x=-15
Find the zeros of (x+7)^2+4=68
The zeros of (x+7)^2+4=68 are x=1,x=-15