What are the solutions to the equation 10^2+x^2=((20sqrt(3))/3)^2 ?

The solutions to the equation 10^2+x^2=((20sqrt(3))/3)^2 are x=(10)/(sqrt(3)),x=-(10)/(sqrt(3))

Find the zeros of 10^2+x^2=((20sqrt(3))/3)^2

The zeros of 10^2+x^2=((20sqrt(3))/3)^2 are x=(10)/(sqrt(3)),x=-(10)/(sqrt(3))

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1 0^{2} + x^{2} = (\frac{20 3}{3})^{2}

x = \frac{10}{3}, x = - \frac{10}{3}

Decimal

x = 5.77350 \dots, x = - 5.77350 \dots

Solution steps

1 0^{2} + x^{2} = (\frac{20 3}{3})^{2}

Expand

1 0^{2} + x^{2} : 100 + x^{2}

Expand

(\frac{20 3}{3})^{2} : \frac{400}{3}

100 + x^{2} = \frac{400}{3}

Move

100

to the right side

x^{2} = \frac{400}{3} - 100

Simplify

\frac{400}{3} - 100 : \frac{100}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{100}{3}, x = - \frac{100}{3}

\frac{100}{3} = \frac{10}{3}

- \frac{100}{3} = - \frac{10}{3}

x = \frac{10}{3}, x = - \frac{10}{3}

- 4 d^{2} + 9 d + 6 = 3 - 7 d

x^{2} - 250 x + 10000 = 0

5 x^{2} - 4 x - 11 = 3 x^{2}

5 x^{2} + 1 = 21

x^{2} - 8 x + 32 = 0

What are the solutions to the equation 10^2+x^2=((20sqrt(3))/3)^2 ?
The solutions to the equation 10^2+x^2=((20sqrt(3))/3)^2 are x=(10)/(sqrt(3)),x=-(10)/(sqrt(3))
Find the zeros of 10^2+x^2=((20sqrt(3))/3)^2
The zeros of 10^2+x^2=((20sqrt(3))/3)^2 are x=(10)/(sqrt(3)),x=-(10)/(sqrt(3))