What are the solutions to the equation y^2=8(y/2) ?

The solutions to the equation y^2=8(y/2) are y=4,y=0

Find the zeros of y^2=8(y/2)

The zeros of y^2=8(y/2) are y=4,y=0

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y^{2} = 8 (\frac{y}{2})

y = 4, y = 0

Solution steps

y^{2} = 8 (\frac{y}{2})

Expand

8 (\frac{y}{2}) : 4 y

y^{2} = 4 y

Move

4 y

to the left side

y^{2} - 4 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

y_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, y_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

y = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

y = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 4, y = 0

3 x^{2} = - 24

\frac{1}{3} x^{2} + x = 0

y, y x^{2} + 2 y = 5 x

y, y^{2} = x^{2} + 6 x + 9

9 p^{2} + 17 p + 12 = 3 p^{2}

What are the solutions to the equation y^2=8(y/2) ?
The solutions to the equation y^2=8(y/2) are y=4,y=0
Find the zeros of y^2=8(y/2)
The zeros of y^2=8(y/2) are y=4,y=0