What is the answer to (4x^2-3x+5)/(x^2-2x+13)=2 ?

The answer to (4x^2-3x+5)/(x^2-2x+13)=2 is x=3,x=-7/2

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(4x^2-3x+5)/(x^2-2x+13)=2

\frac{4 x ^{2} - 3 x + 5}{x ^{2} - 2 x + 13} = 2

x = 3, x = - \frac{7}{2}

Decimal

x = 3, x = - 3.5

Solution steps

\frac{4 x ^{2} - 3 x + 5}{x ^{2} - 2 x + 13} = 2

Multiply both sides by

x^{2} - 2 x + 13

4 x^{2} - 3 x + 5 = 2 (x^{2} - 2 x + 13)

Solve

4 x^{2} - 3 x + 5 = 2 (x^{2} - 2 x + 13) : x = 3, x = - \frac{7}{2}

x = 3, x = - \frac{7}{2}

x + \frac{1}{x} = \frac{6 5}{5}

5 x - \frac{1}{x} = 4

4 x - \frac{36}{x} = 0

\frac{x - 4}{x} + \frac{x ^{- 1}}{3} = - 2

\frac{2}{x} = \frac{8}{32}

What is the answer to (4x^2-3x+5)/(x^2-2x+13)=2 ?
The answer to (4x^2-3x+5)/(x^2-2x+13)=2 is x=3,x=-7/2
Solve for x: (4x^2-3x+5)/(x^2-2x+13)=2
The solution is x=3,x=-7/2