What is the answer to 8+36u^{-2}=41u^{-1} ?

The answer to 8+36u^{-2}=41u^{-1} is u=4,u= 9/8

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8+36u^{-2}=41u^{-1}

8 + 36 u^{- 2} = 41 u^{- 1}

u = 4, u = \frac{9}{8}

Decimal

u = 4, u = 1.125

Solution steps

8 + 36 u^{- 2} = 41 u^{- 1}

Refine

8 + \frac{36}{u ^{2}} = \frac{41}{u}

Multiply by LCM

8 u^{2} + 36 = 41 u

Solve

8 u^{2} + 36 = 41 u : u = 4, u = \frac{9}{8}

u = 4, u = \frac{9}{8}

Verify Solutions

Find undefined (singularity) points:

u = 0

Combine undefined points with solutions:

u = 4, u = \frac{9}{8}

4 x - \frac{4}{x} = 0

\frac{2 x - 3}{x + 6} = \frac{5}{4}

\frac{1}{x + 2} + \frac{3}{x - 2} = 0

\frac{2.04}{x} = \frac{1.57}{x - 0.028}

\frac{4}{x + 4} = \frac{6}{x}

What is the answer to 8+36u^{-2}=41u^{-1} ?
The answer to 8+36u^{-2}=41u^{-1} is u=4,u= 9/8
Solve for u: 8+36u^{-2}=41u^{-1}
The solution is u=4,u= 9/8